JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

\frac{\cos A}{3}=\frac{\cos B}{4}=\frac{1}{5},-\frac{\pi}{2} < (A, B) < 0

, then value of

2 \sin A+4 \sin B

View answer and explanation

Correct option: C

-4

Option C (-4) is correct because given the conditions, we find

\sin A = -\frac{4}{5}

and

\sin B = -\frac{3}{5}

. Substituting these values into

2 \sin A + 4 \sin B

gives

2(-\frac{4}{5}) + 4(-\frac{3}{5}) = -\frac{8}{5} - \frac{12}{5} = -4

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