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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy
1 of 1
Application +4 | -1
For x∈IR,  3cos⁡  (4x−5)+4x \in IR,\,\,3\cos \,\,\left( {4x - 5} \right) + 4 lies in the interval
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Correct option: A
[1,7]\left[ {1,\mathrm{ }7} \right]
Option A ([1, 7]) is correct because the minimum value of 3cos⁡(4x−5)3\cos(4x-5) is -3 and the maximum value is 3, so the range of 3cos⁡(4x−5)+43\cos(4x-5) + 4 is [1, 7].

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