JEE PHYSICS MCQ: OSCILLATIONS

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A uniform spring has an unstreched length

\lambda

and a force constant

\mathrm{k}

. The spring is cut into two parts of unstreched length

\lambda_1

and

\lambda_2

such that

\lambda_1=\eta \lambda_2

where

\eta

is an integer. The corresponding force constants

\mathrm{k}_1

and

\mathrm{k}_2

are :

View answer and explanation

Correct option: D

\frac{\mathrm{k}(\eta+1)}{\eta}

and

\mathrm{k}(\eta+1)

The correct answer is D. The force constant is inversely proportional to the length of the spring, so when the spring is cut, the force constants change accordingly.

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