JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

Two kg of water is converted into steam by boiling at atmospheric pressure. The volume changes from

2 \times {10^{ - 3}}{m^3}

3.34{m^3}

. The work done by the system is about

View answer and explanation

Correct option: D

340kJ

Option D (

340kJ

) is correct because the work done is calculated by multiplying the pressure by the change in volume.

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\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)