For ${\rm{\theta }} > {\rm{\pi }}/3,$ the value of $f\left( {\rm{\theta }} \right) = {\sec ^2}{\rm{\theta }} + {\cos ^2}{\rm{\theta }}$ always lies in the interval

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

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Analyzing +4 | -1

For

\mathrm{\theta } > \mathrm{\pi }/3,

the value of

f\left( \mathrm{\theta } \right) = {\sec ^2}\mathrm{\theta } + {\cos ^2}\mathrm{\theta }

always lies in the interval

View answer and explanation

Correct option: D

\left[ {2,\infty } \right)

Option D (

[2,\infty)

) is correct because the minimum value of the function is 2, and it can go to infinity.