JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

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Application +4 | -1

\int \frac{1}{x^2 \sqrt{1+x^2}} d x=

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Correct option: A

-\frac{\sqrt{1+x^2}}{x}+c

Option A is correct because the integral evaluates to

-\frac{\sqrt{1+x^2}}{x} + c

after applying the trigonometric substitution.

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