JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

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Application +4 | -1

Value of the integral

\int {{e^x}\left[ {\frac{{1 + \sqrt {1 - {x^2}} {{\sin }^{ - 1}}x}}{{\sqrt {1 - {x^2}} }}} \right]dx}

is equal to

View answer and explanation

Correct option: A

{e^x}{\sin ^{ - 1}}x + c

Option A (

{e^x}{\sin ^{ - 1}}x + c

) is correct because the integral can be simplified using integration by parts, resulting in this expression.

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