JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Analyzing +4 | -1

a,\,\,b,\,\,c

denote the sides of a

\Delta \,ABC

and the equations

a{x^2} + bx + c = 0

and

{x^2} + \sqrt 2 x + 1 = 0

have a common root, then

\angle \,C =

View answer and explanation

Correct option: B

45^\circ

Option B (

45^\circ

) is correct because the common root implies that the ratio of coefficients of the two equations are equal, leading to

A = C = 45^\circ

More Questions from PROPERTIES OF TRIANGLES

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{p_1},{p_2},{p_3}

\Delta \;ABC

A,B,C

\Delta

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5k,\;6k,\;5k

k

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

2 s