JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

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Application +4 | -1

In triangle

A B C

\frac{[\Delta A B C]}{R}=4

, then the value of

a \cos A+b \cos B+c \cos C

, is:
[

R

is the circumradius of triangle

A B C

and

[\Delta A B C]

is the area of

\Delta A B C]

View answer and explanation

Correct option: C

Option C is correct because using trigonometric identities and the area formula, the expression simplifies to 8.

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