JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Analyzing +4 | -1

Find

A,\,\,B

and

C

in the following reactions:

\begin{array}{l} N{H_3}\, + \,A\, + \,C{O_2} \to {(N{H_4})_2}C{O_3}\\ {(N{H_4})_2}C{O_3}\, + \,{H_2}O\, + \,B \to N{H_4}HC{O_3}\\ N{H_4}HC{O_3}\, + \,NaCl \to N{H_4}CI\, + \,C \end{array}

View answer and explanation

Correct option: D

A - {H_2}O,\,\,B - C{O_2},\,\,C - NAHC{O_3}

Option D (

A - {H_2}O,\,B - C{O_2},\,C - NAHC{O_3}

) is correct because it accurately represents the reactants involved in the Solvay process for the production of sodium bicarbonate.

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