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JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Two particles of equal mass have velocities v1=4i^ and v2=4j^ ms−1{v_1} = 4\hat i\,and\,{v_2} = 4\hat j\,m{s^{ - 1}}. First particle has an acceleration a1=(5i^+5j^)ms−2{a_1} = \left( {5\hat i + 5\hat j} \right)m{s^{ - 2}} , while the acceleration of the other particle is zero. The centre of mass of the two particles moves in a path of
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Correct option: A
Straight line
Option A (Straight line) is correct because the center of mass has a constant acceleration, resulting in a straight-line path.

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