JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

If the amount of heat given to a system is

35J

and the amount of work done on the system is

15J

, then the change in internal energy of the system is

View answer and explanation

Correct option: D

50J

Option D (50J) is correct because the change in internal energy is calculated using the first law of thermodynamics:

\Delta U = \Delta Q - \Delta W

, considering the sign convention for work done on the system.

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