JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1

\int \cos \left\{2 \tan ^{-1} \sqrt{\frac{1-x}{1+x}}\right\} d x

is equal to

View answer and explanation

Correct option: B

\frac{1}{2} x^2+C

Option B (

\frac{{1}}{{2}} x^2+C

) is correct because by using the substitution

x = \cos 2\theta

, the integral simplifies to

\frac{{1}}{{2}}x^2 + C

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