JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

The domain of definition of the function

f\left( x \right) = {\log _2}\left[ { - {{\left( {{{\log }_2}x} \right)}^2} + 5{{\log }_2}x - 6} \right],

View answer and explanation

Correct option: A

\left( {4,8} \right)

Option A

\left( {4,8} \right)

is correct because the domain is found by solving the inequality resulting from the logarithm's argument being greater than zero.

More Questions from FUNCTIONS

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}