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JEE MATHEMATICS MCQ: MAXIMA & MINIMA

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Analyzing +4 | -1
Let f(x)=sin⁡xcos⁡2x,x∈[0,π]f(x)=\sin x \cos ^2 x, x \in[0, \pi]. Let mm be the number of values of xx at which f(x)f(x) is minimum and nn be the number of values of xx at which f(x)f(x) is maximum. Then
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Correct option: D
m=1,n=2m=1, n=2
Option D (m=1,n=2m=1, n=2) is correct because the function has one minimum and two maxima in the given interval.

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