If ${C^2} + {S^2} = 1,$ then $\frac{{1 + C + i\;S}}{{1 + C - i\;S}}$ is equal to

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

{C^2} + {S^2} = 1,

then

\frac{{1 + C + i\;S}}{{1 + C - i\;S}}

is equal to

View answer and explanation

Correct option: A

C + i\;S

Option A (

C + i\;S

) is correct because it is the simplified form of the given expression using trigonometric identities.

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