JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

The equation arg

\left( {\frac{{z - 1}}{{z + 1}}} \right) = \frac{\pi }{4}

represents a circle with

View answer and explanation

Correct option: B

centre at (0, 1) and radius

\sqrt 2

Option B is correct because the given equation represents a circle in the complex plane with center (0, 1) and radius

\sqrt{2}

, derived by converting to Cartesian coordinates.

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{\left| {1 - i} \right|^x} = {2^x}

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z \neq \pm 1

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\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

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\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

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