JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

f(x)=\cos (\log x)

, then

f\left(x^{2}\right) f\left(y^{2}\right)-\frac{1}{2}\left[f\left(\frac{x^{2}}{2}\right)+f\left(\frac{x^{2}}{y^{2}}\right)\right]

has the value

View answer and explanation

Correct option: D

None of these

Option D (None of these) is correct because the given expression simplifies to

\frac{{1}}{{2}}\left[\cos \log x^2 y^2-\cos \log \frac{{x^2}}{{2}}\right]

, which doesn't match any of the provided options.

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