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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

A particle is subjected to two simple harmonic motions

x_1=A_1 \sin \omega t

and

x_2=A_2 \sin (\omega t+\pi / 3)

Find

(a) the displacement at

t=0

(b) the maximum speed of the particle.

View answer and explanation

Correct option: A

(a)

\frac{A_2 \sqrt{3}}{2};

(b)

\omega \sqrt{A_1^2+A_2^2+A_1 A_2}

Option A (a)

\frac{A_2 \sqrt{3}}{2};

(b)

\omega \sqrt{A_1^2+A_2^2+A_1 A_2}

is correct because it correctly calculates the displacement at t=0 and the maximum speed of the particle.

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