JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Suppose that

f

is a periodic function with period

\frac{1}{2}

and that

f(2)=5

and

f\left(\frac{9}{4}\right)=2

then

f(-3)-f\left(\frac{1}{4}\right)

has the value equal to

View answer and explanation

Correct option: B

Option B (3) is correct because it represents the value of

f(-3) - f(\frac{{1}}{{4}})

calculated using the periodicity of the function.

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}