JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Application +4 | -1

Let

f(\theta)=(1+\cos \theta)(1+\cos 3 \theta)

(1+\cos 5 \theta)(1+\cos 7 \theta)

then

f\left(-\frac{\pi}{8}\right)

is equal to:

View answer and explanation

Correct option: D

1 / 8

The correct answer is D (1/8) because by using the property f(-θ) = f(θ) and trigonometric identities, we can simplify the expression to obtain the result.

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\tan \alpha=\frac{p}{q}

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\alpha=6 \beta

and

\alpha

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\frac{1}{2}[p \operatorname{cosec} 2 \beta-q \sec 2 \beta]

is equal to The value of

\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

is If the

\triangle A B C

is acute angled at

C

, then The value of the expression

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

equals

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=