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JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

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The number of circles belonging to the system of circles 2(x2+y2)+λ  x−(1+λ2)y−10=02\left( {{x^2} + {y^2}} \right) + \lambda \;x - \left( {1 + {\lambda ^2}} \right)y - 10 = 0 and orthogonal to x2+y2+4x+6y+3=0,{x^2} + {y^2} + 4x + 6y + 3 = 0, is
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Correct option: A
2
The correct answer is A (2). By finding the condition for orthogonality between the circles, a quadratic equation in λ\lambda is obtained, yielding two possible values for λ\lambda, hence two circles.

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