JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Medium

1 of 1

Application +4 | -1

In a triangle

ABC,\,\,\frac{{a\,\,\cos \,\,A + b\,\,\cos \,\,B + c\,\,\cos \,\,C}}{{a + b + c}}

is equal to

View answer and explanation

Correct option: A

\frac{r}{R}

Option A (

\frac{r}{R}

) is correct because, using trigonometric identities and the sine rule, the given expression simplifies to

\frac{r}{R}

, where

r

is the inradius and

R

is the circumradius of the triangle.

More Questions from PROPERTIES OF TRIANGLES

Practice All Chapter MCQs →

{p_1},{p_2},{p_3}

\Delta \;ABC

A,B,C

\Delta

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

5k,\;6k,\;5k

k

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

2 s