When $110 \mathrm{~g}$ of manganese (At. mass $=55$ ) dissolves in dilute $\mathrm{HNO}_3$ at $27^{\circ} \mathrm{C}$ under atmospheric pressure, the work done in the process is :

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

1 Hard

1 of 1

Application +4 | -1

When

110 \mathrm{~g}

of manganese (At. mass

=55

) dissolves in dilute

\mathrm{HNO}_3

27^{\circ} \mathrm{C}

under atmospheric pressure, the work done in the process is :

View answer and explanation

Correct option: C

-4988.4 \mathrm{~J}

Option C (

-4988.4 \mathrm{~J}

) is correct because the work done is negative, indicating expansion against atmospheric pressure, and is calculated using

W = -P\Delta V = -\Delta nRT

Practice All Chapter MCQs →

{T_i}

{T_f}

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

\Delta G