$\smallint \left( {1\,\, + \,\,x\,\, - \,\,{x^{ - 1}}} \right){e^{x + {x^{ - 1}}}}\,dx$ is equal to

$\left( {1\,\, + \,\,x} \right){e^{x + {x^{ - 1}}}} + \,\,c$

$\left( {x\,\, - \,\,1} \right){e^{x + {x^{ - 1}}}} + \,\,c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \left( {1\,\, + \,\,x\,\, - \,\,{x^{ - 1}}} \right){e^{x + {x^{ - 1}}}}\,dx

is equal to

View answer and explanation

Correct option: D

x{e^{x + {x^{ - 1}}}} + \,\,c

Option D (

x{e^{x + {x^{ - 1}}}} + \,c

) is correct because it is the result of integrating the given expression using integration by parts.