JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

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Application +4 | -1

Let

g\left( x \right) = \;\left\{ {\begin{array}{cccccccccccccccccccc} {2e\;\;\;\;\;\;\;\;\;\;\;\;\;if\;x \le 1}\\ {\mathrm{\;log}\left( {x - 1} \right),\;\;\;if\;\;x > 1} \end{array}} \right.\;

. The equation of the normal to

y = g\left( x \right)

at the point (3,log 2), is

View answer and explanation

Correct option: B

y + 2x = 6 + \log 2

Option B (

y + 2x = 6 + \log 2

) is correct because it represents the equation of the normal line to the curve at the given point, calculated using the derivative.

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y=x^3-a x

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\mathrm{C}

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y-e^{x y}+x=0

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x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z