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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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Application +4 | -1
Water rises up in a glass capillary upto a height of 9.0 cm9.0 \mathrm{~cm}, while mercury falls down by 3.4 cm3.4 \mathrm{~cm} in the same capillary. Assume angles of contact for water-glass and mercury-glass as 0∘0^{\circ} and 135∘135^{\circ} respectively. Determine the ratio of surface tensions of mercury and water. Take cos⁡135∘=−0.71.\cos 135^{\circ}=-0.71.
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Correct option: A
7.2:17.2: 1
Option A (7.2:17.2: 1) is correct because it is the ratio of surface tensions calculated using the capillary rise formula, considering the different heights, densities, and contact angles.

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