Question

$\smallint \,\,\frac{1}{{\sin \,\,\left( {x - a} \right)\,\,\cos \,\,\left( {x - b} \right)}}\,\,dx$ is equal to

Accepted Answer

$\frac{1}{{\cos \,\,\left( {a - b} \right)}}\,\,\log \,\,\left| {\,\frac{{\sin \,\,\left( {x - a} \right)}}{{\cos \,\,\left( {x - b} \right)}}\,} \right| + C$

Answer

$\frac{1}{{\sin \,\,\left( {a - b} \right)}}\,\,\log \,\,\left| {\,\frac{{\sin \,\,\left( {x - a} \right)}}{{\cos \,\,\left( {x - b} \right)}}\,} \right| + C$

Answer

$\frac{1}{{\sin \,\,\left( {a + b} \right)}}\,\,\log \,\,\left| {\,\frac{{\sin \,\,\left( {x - a} \right)}}{{\cos \,\,\left( {x - b} \right)}}\,} \right| + C$

Answer

$\frac{1}{{\cos \,\,\left( {a + b} \right)}}\,\,\log \,\,\left| {\,\frac{{\sin \,\,\left( {x - a} \right)}}{{\cos \,\,\left( {x - b} \right)}}\,} \right| + C$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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