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JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Application +4 | -1
The numbers P,Q and R for which the function f(x)=Pe2x+Qex+Rxf\left( x \right) = P{e^{2x}} + Q{e^x} + Rx satisfies the conditions f(0)=−1, f1(log⁡2)=31f\left( 0 \right) = - 1,\,{f^1}\left( {\log 2} \right) = 31 and ∫0log⁡4[f(x)−Rx]dx=392\int_0^{\log 4} {\left[ {f\left( x \right) - Rx} \right]dx=\frac{{39}}{2}} are given by
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Correct option: D
P=5, Q=-6, R=3
Option D (P=5, Q=-6, R=3) is correct because these values satisfy all the given conditions for the function f(x).

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