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JEE MATHEMATICS MCQ: MATHEMATICAL REASONING

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If (p∧∼r)⇒(q∨r)(p \wedge \sim r) \Rightarrow(q \vee r) is false and qq and rr are both false, then pp is
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Correct option: A
TRUE
Option A (TRUE) is correct because if (p∧∼r)⇒(q∨r)(p \wedge \sim r) \Rightarrow (q \vee r) is false, then (p∧∼r)(p \wedge \sim r) must be true and (q∨r)(q \vee r) must be false. Since rr is false, ∼r\sim r is true, and for (p∧∼r)(p \wedge \sim r) to be true, pp must be true.

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