JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Analyzing +4 | -1

1, \omega, \omega^2, \omega^3, \ldots, \omega^{n-1}

are the

n^{\text {th }}

roots of unity, then

(1-\omega)\left(1-\omega^2\right)\left(1-\omega^3\right) \ldots\left(1-\omega^{n-1}\right)

View answer and explanation

Correct option: C

n

Option C (

n

) is correct because the given expression is equal to the derivative of

z^n - 1 = 0

evaluated at z=1, which results in n.

More Questions from COMPLEX NUMBERS

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{\left| {1 - i} \right|^x} = {2^x}

|z|=1

z \neq \pm 1

z, \frac{z}{1-z^2}

\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

a \neq 0

\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}