JEE MATHEMATICS MCQ: TRANSFORMATION OF AXES

1 Easy

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Application +4 | -1

p

and

p^{\prime}

are the lengths of perpendiculars drawn from the origin to lines

x \sec \theta+y \operatorname{cosec} \theta=2 a

and

x \cos \theta+y \sin \theta=a \cos 2 \theta

respectively, then

\left(\frac{p}{p^{\prime}}+\frac{p^{\prime}}{p}\right)^2=\ldots \ldots

View answer and explanation

Correct option: B

4 \operatorname{cosec}^2 4 \theta

Option B (

4 \operatorname{cosec}^2 4 \theta

) is correct because it represents the simplified form of the expression

\left(\frac{p}{p^{\prime}}+\frac{p^{\prime}}{p}\right)^2

after substituting the values of

p

and

p^{\prime}

and using trigonometric identities.

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