JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

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Application +4 | -1

The length of the normal to the curve

y=a\left(\frac{e^{-x / a}+e^{x / a}}{2}\right)

at any point varies as the

View answer and explanation

Correct option: D

Square of the ordinate of the point

Option D (Square of the ordinate of the point) is correct because the length of the normal varies as the square of the ordinate.

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a

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x y=1-y

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y^3-3 x y+2=0

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\mathrm{C}

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y-e^{x y}+x=0

y = f\left( x \right)

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x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z