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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫(x2−x−1x+1)K+7(x2+1x2)dx\int\left(\frac{x^2-x-1}{x}+1\right)^{K+7}\left(\frac{x^2+1}{x^2}\right) d x is equal to
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Correct option: B
(x−1x)K+8k+8+c\frac{\left(x-\frac{1}{x}\right)^{K+8}}{k+8}+c
Option B ((x−1x)K+8k+8+c\frac{(x-\frac{1}{x})^{K+8}}{k+8}+c) is correct because substituting t=x−1xt = x - \frac{1}{x} simplifies the integral to a basic power rule integration.

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