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JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy
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Application +4 | -1
x2−3∣x∣+2<0,  {x^2} - 3\left| x \right| + 2 < 0,\; then xx belongs to
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Correct option: C
(−2,−1)∪(1,2)\left( { - 2, - 1} \right) \cup \left( {1,2} \right)
Option C is correct because solving the inequality with absolute values leads to the solution set (-2, -1) ∪ (1, 2).

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