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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
In a Δ ABC,  sin⁡  A\Delta \,ABC,\,\,\sin \,\,A and sin⁡  B\sin \,\,B are the roots of the equation c2 x2−c(a+b)x+ab=0{c^2}\,{x^2} - c\left( {a + b} \right)x + ab = 0, then sin⁡  C=\sin \,\,C =
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Correct option: C
1\mathrm{1}
Option C (1\mathrm{1}) is correct because sin⁡C=1\sin C = 1 is derived directly from the relationship between the sides and angles of the triangle using the given equation.

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