${\rm{N}}{{\rm{a}}_2}{\rm{S}} + {\rm{N}}{{\rm{a}}_2}\left[ {{\rm{Fe}}{{\left( {{\rm{CN}}} \right)}_5}{\rm{NO}}} \right]$ $ \to $ Purple colour. It is due to

${\rm{N}}{{\rm{a}}_4}\left[ {{\rm{Fe}}{{\left( {{\rm{CN}}} \right)}_5}{\rm{NOS}}} \right]$

${\rm{N}}{{\rm{a}}_4}\left[ {{\rm{Fe}}{{\left( {{\rm{CN}}} \right)}_3}{\rm{NOS}}} \right]$

${\rm{N}}{{\rm{a}}_3}\left[ {{\rm{Fe}}{{\left( {{\rm{CN}}} \right)}_5}{\rm{NOS}}} \right]$

${\rm{N}}{{\rm{a}}_4}\left[ {{\rm{Fe}}{{\left( {{\rm{CN}}} \right)}_5}{\rm{NO}}} \right]$

NEET UG CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

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Understanding +4 | -1

\mathrm{N}{\mathrm{a}_2}\mathrm{S} + \mathrm{N}{\mathrm{a}_2}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_5}\mathrm{NO}} \right]

\to

Purple colour. It is due to

View answer and explanation

Correct option: D

\mathrm{N}{\mathrm{a}_4}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_5}\mathrm{NOS}} \right]

Option D (

\mathrm{N}{\mathrm{a}_4}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_5}\mathrm{NOS}} \right]

) is correct because the purple color in the test for both nitrogen and sulfur is due to the formation of sodium nitroprusside,

Na_4[Fe(CN)_5NOS]