Skip to main content
Back to FUNCTIONS

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy
1 of 1
Application +4 | -1
If f:[−2,  2]→Rf:\left[ { - 2,\;2} \right] \to R is defined by

f(x)={−1,    for−2≤x≤0x−1,    for  0≤x≤2f\left( x \right) = \left\{ {\begin{array}{cccccccccccccccccccc} { - 1,\;\;for - 2 \le x \le 0}\\ {x - 1,\;\;for\;0 \le x \le 2} \end{array}} \right.

Then {x∈[−2,2]:x≤0    and    f(∣x∣)=x}=\left\{ {x \in \left[ { - 2,2} \right]:x \le 0\;\;\mathrm{and}\;\mathrm{\;}f\left( {\left| x \right|} \right) = x} \right\} =
View answer and explanation
Correct option: C
{−1/2}\left\{ { - 1/2} \right\}
Option C ({-1/2}) is correct because by substituting |x| into the function and solving for x, we find x = -1/2.

More Questions from FUNCTIONS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.