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JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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The order and degree of the differential equation y+d2ydx2=x+(dydx)32\sqrt {y + \frac{{{d^2}y}}{{d{x^2}}}} = x + {\left( {\frac{{dy}}{{dx}}} \right)^{\frac{3}{2}}} are
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Correct option: A
2,22,2
Option A (2,2) is correct because, after squaring twice to remove the square roots, the highest order derivative is 2 and its power is 2.

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