JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy

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Analyzing +4 | -1

If the points

\left( {{a_1},{b_1}} \right),\left( {{a_2},{b_2}} \right)

and

\left( {{a_3},{b_3}} \right)

are collinear, then lines

{a_i}x + {b_i}y + 1 = 0

for

{a_i}x + {b_i}y + 1 = 0

are

View answer and explanation

Correct option: A

Concurrent

Option A (Concurrent) is correct because the collinearity of the points implies that the determinant formed by their coordinates is zero, which is also the condition for concurrency of the given lines.

More Questions from STRAIGHT LINES

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If the three lines

x-3 y=p, a x+2 y=q

and

a x+y=r

form a right-angled triangle then :
The orthocentre of the triangle whose vertices are

\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

is
The distance between the parallel lines

y = 2\;x + 4

and

6x = 3y + 5

is The distance between the pair of lines given by

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

is Find the image of the point

(3,8)

with respect of the line

x+3 y=7

assuming the line to be plane mirror: The centroid of the triangle whose three sides are given by the combined equation

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0