Dual of ${\left( {x' \vee y'} \right)^\prime } = x \wedge y$ is

$\left( {x' \vee y'} \right) = x \vee y$

${\left( {x' \wedge y'} \right)^\prime } = x \wedge y$

JEE MATHEMATICS MCQ: MATHEMATICAL REASONING

1 Easy

1 of 1

Understanding +4 | -1

Dual of

{\left( {x' \vee y'} \right)^\prime } = x \wedge y

View answer and explanation

Correct option: B

{\left( {x' \wedge y'} \right)^\prime } = x \vee y

Option B is correct because the dual of a statement is obtained by replacing

\wedge

with

\vee

\vee

with

\wedge

, 0 with 1, and 1 with 0.

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p:A

q:A

\sqrt{3}

p

q

p \rightarrow q

{F_1}(A,\,B,\,C) = \left( {A \wedge \sim B} \right) \vee \left[ { \sim C \wedge \left( {A \vee B} \right)} \right] \vee \sim A

{F_2}(A,\,B) = \left( {A \vee B} \right) \vee (B \to \, \sim \,A)

p

n

q:

n

p \Leftrightarrow q