JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

A particle of mass 1 kg is projected with an initial velocity 10 

\mathrm{m}{\mathrm{s}^{ - 1}}

  at an angle of projection

{45^0}

with the horizontal. The average torque acting on the projectile, between the time at which it is projected and the time at which it strikes the ground, about the point of projection in newton-metre is

View answer and explanation

Correct option: B

Option B (50) is correct because the average torque is calculated using the rate of change of angular momentum, which simplifies to

m(u^2 \cos^2 \theta)

More Questions from SYSTEM OF PARTICLES

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It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

of length

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

, where

x

is measured from

\mathrm{A}

. If the

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

from

\mathrm{A}

, then a and

\mathrm{b}

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)