JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

Z=x+i y

be a complex number,

Z^{\frac{1}{3}}=a-i b

and

\frac{x}{a}-\frac{y}{b}=\lambda\left(a^2-b^2\right)

, (where

x, y, a, b

and

\lambda

are positive real numbers) then the value of

\lambda

View answer and explanation

Correct option: C

Option C (4) is correct because by cubing

Z^{\frac{{1}}{{3}}}=a-ib

and equating real and imaginary parts, we find that

\frac{{x}}{{a}}-\frac{{y}}{{b}} = 4(a^2 - b^2)

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