JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

f\left( x \right) = {\left( {\frac{x}{{1 - \left| x \right|}}} \right)^{1/2002}}

then

{D_f}

View answer and explanation

Correct option: C

\left( { - \infty ,\; - 1} \right) \cup \left( {0,\;1} \right)

Option C (

\left( { - \infty ,\\; - 1} \right) \cup \left( {0,\\;1} \right)

) is correct because the expression inside the square root must be positive, leading to the specified domain.

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