Question

If $x\,\,\cos \,\,\alpha + y\sin \,\,\alpha = 2a,\;\,x\,\,\cos \,\,\alpha + y\,\,\sin \,\,\beta = 2a$ and $2\sin \,\,\frac{\alpha }{2}\,\,\sin \,\,\frac{\beta }{2} = 1$, then

Accepted Answer

${y^2} = 4a\,\,\left( {\alpha - x} \right)$

Answer

$\cos \,\,\alpha + \cos \,\,\beta = \frac{{2ax}}{{{x^2} + {y^2}}}$

Answer

$\cos \,\,\alpha \,\,\cos \,\,\beta = \frac{{2{a^2} - {y^2}}}{{{x^2} + {y^2}}}$

Answer

$\cos \,\,\alpha + \cos \,\,\beta = 2\,\,\cos \,\,\alpha \,\,\cos \,\,\beta $

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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