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JEE PHYSICS MCQ: KINETIC THEORY OF GASES

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A vessel contains 14 g14 \mathrm{~g} of nitrogen gas at a temperature of 27∘C27^{\circ} \mathrm{C}. The amount of heat to be transferred to the gas to double the r.m.s speed of its molecules will be:

Take R=8.32 J mol−1 K−1R=8.32 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}.
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Correct option: C
9360 J
Option C (9360 J) is correct because it is the amount of heat required to double the RMS speed, calculated using the specific heat at constant volume.

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