How many lone pair of electrons are present on $Xe$ in $XeO{F_4}$ ?

JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

1 Easy

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How many lone pair of electrons are present on

Xe

XeO{F_4}

View answer and explanation

Correct option: A

Option B (2) is correct because a 3p orbital has one angular node (l=1) and one radial node (n-l-1 = 3-1-1 = 1).

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17^{\text {th }}

{O}_2

{O}_2

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

{H}_2 {SO}_4

{H}_2 {SO}_4