Skip to main content
Back to COMPLEX NUMBERS

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy
1 of 1
Analyzing +4 | -1
If the equation a∣z∣2+α‾z+αz‾‾+d=0a{\left| z \right|^2} + \overline {\overline \alpha z + \alpha \overline z } + d = 0 represents a circle, where a, da,\,d are real constants, then which of the following condition is correct?
View answer and explanation
Correct option: B
∣α∣2−ad>0  and  a∈R−{0}{\left| \alpha \right|^2} - ad > 0\,\,\mathrm{and}\,\,a \in R - \{ 0\}
Option B (∣α∣2−ad>0, mathrmand, a∈R−0{\left| \alpha \right|^2} - ad > 0\\,\,\\mathrm{and}\\,\,a \in R - \\{ 0\\}) is correct because it represents the condition for the given equation to represent a circle.

More Questions from COMPLEX NUMBERS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.