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JEE MATHEMATICS MCQ: CIRCLES

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Application +4 | -1
If the circle x2+y2+4x+22y+I=0x^2+y^2+4 x+22 y+I=0 bisects the circumference of the circle x2+y2−2x+8y−m=0x^2+y^2-2 x+8 y-m=0, then l+ml+m is equal to
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Correct option: B
50
Option B (50) is correct because the condition for one circle bisecting the circumference of another leads to the equation l+m=50l+m=50.

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