JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Understanding +4 | -1

Let

f\left( x \right) = \left| {x - 2} \right| + \left| {x - 3} \right| + \left| {x - 4} \right|\;and\;g\left( x \right) = x + 1.

Then,

View answer and explanation

Correct option: C

g\left( x \right)

is neither even nor odd

Option C (

g(x)

is neither even nor odd) is correct because

g(-x) \ne g(x)

and

g(-x) \ne -g(x)

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}